Question 2 9 Consider the ROM table ( AKA State Transition Table ) below If you created the associated programming table, what would the DATA entry be for the ADDRESS ( B H ) begin tabular c c c c c c c c c hline multicolumn 7 l ROM TABLE multicolumn 2 l hline multicolumn 2 l multirow t 2 begin tabular l Present State ( mathrm A 3 mathrm A 2 ) end tabular multicolumn 2 l Inputs multicolumn 2 l multirow t 2 begin array c text Next text State D 4 quad D 3 end array multirow t 2 Output ( D 2 ) multicolumn 2 l begin tabular l Decoder Select end tabular hline A ( mathrm A 0 ) ( mathrm D 1 ) ( mathrm D 0 ) hline A B IN 1 IN 0 A B LWAX SDA SDB hline 0 0 0 0 0 0 1 0 0 hline 0 0 0 1 0 0 1 0 0 hline 0 0 1 X 0 0 1 0 0 hline 0 1 X 0 1 0 , 0 1 hline 0 1 0 1 0 1 1 0 0 hline 0 1 1 1 1 1 1 0 0 hline 0 0 0 1 0 0 1 0 hline 1 0 0 1 1 0 1 1 0 hline 1 0 1 0 1 1 0 1 0 hline 1 0 1 1 1 1 1 1 0 hline 1 1 X X 0 0 1 1 1 hline end tabular 0 7 Hex 0 4 Hex 1 A Hex 1 E Hex

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Question: Question 2 9 Consider the ROM table ( AKA State Transition Table ) below. If you created the associated programming table, what would the DATA

Question

29

Consider the ROM table

(

AKA State Transition Table

)

below. If you created the associated programming table, what would the DATA entry be for the ADDRESS

\ (=

_{

} \) ?

\

begin

{

tabular

} {|

|

|

|

|

|

|

|

|

|}

\

hline

\

multicolumn

{7} {|

|} {

ROM TABLE:

}

\

multicolumn

{2} {|

|} {} \ \

\

hline

\

multicolumn

{2} {|

|} {\

multirow

[

] {2} {*} {\

begin

{

tabular

} {

}

Present

State

\ \

\ (\

mathrm

{

}_{3} \

mathrm

{

}_{2} \)

\

end

{

tabular

}}}

\

multicolumn

{2} {|

|} {

Inputs

}

\

multicolumn

{2} {|

|} {\

multirow

[

] {2} {*} {\ [

\

begin

{

array

} {

}

\

text

{

} \ \

\

text

{

State

} \ \

_{4} \

quad D

_{3}

\

end

{

array

}

\]}}

\

multirow

[

] {2} {*} {

Output

\ (

_{2} \)}

\

multicolumn

{2} {|

|} {\

begin

{

tabular

} {

}

Decoder

\ \

Select

\

end

{

tabular

}} \ \

\

hline & & A &

\ (\

mathrm

{

}_{0} \)

& & & &

\ (\

mathrm

{

}_{1} \)

\ (\

mathrm

{

}_{0} \) \ \

\

hline A & B & IN

1

& IN

0

& A & B & LWAX & SDA & SDB

\ \

\

hline

0

0

0

0

0

0

1

0

0 \ \

\

hline

0

0

0

1

0

0

1

0

0 \ \

\

hline

0

0

1

& X &

0

0

1

0

0 \ \

\

hline

0

1

& X &

0

1

0

,

0

1 \ \

\

hline

0

1

0

1

0

1

1

0

0 \ \

\

hline

0

1

1

1

1

1

1

0

0 \ \

\

hline

0

0

0

1

0

0

1

0 \ \

\

hline

1

0

0

1

1

0

1

1

0 \ \

\

hline

1

0

1

0

1

1

0

1

0 \ \

\

hline

1

0

1

1

1

1

1

1

0 \ \

\

hline

1

1

& X & X &

0

0

1

1

1 \ \

\

hline

\

end

{

tabular

}

07

Hex

04

Hex

1

A Hex

1

E Hex

Question 2 9 Consider the ROM table ( AKA State

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