Question $2$: A manually cleaned bar screen is inclined at a $\backslash (60^\{\backslash$circ$\}\backslash )$ angle from the horizontal line. The flow of water through the screen has a rate of $\backslash (0\mathrm{.}3\backslash$mathrm$\{$~m$\}3/\backslash$mathrm$\{$s$\}\backslash ).$ The screen consists of $120$ bars given that the width of the bars is $1\mathrm{.}5$ mm $,$ and the size of opening between bars is $25.$ The overall submerged area of the screen is $\backslash (0\mathrm{.}5\backslash$mathrm$\{$~m$\}^\{2\}\backslash ).$ Consider flow coefficient for clogged bar rack as $0\mathrm{.}6,$ cleaned bar rack as $0\mathrm{.}7.$ Calculate the maximum allowable clogged percentage of the screen.

Hint: Consider the maximum allowable head loss for bar racks