Question: Assuming MPL= 2 min, T = Imin20s and A 800ms, and a transmission rate of 2.8 Mbps, what is the smallest possible sequence number
Assuming MPL= 2 min, T = Imin20s and A 800ms, and a transmission rate of 2.8 Mbps, what is the smallest possible sequence number size if the packet size is at least 48 bytes? %3D (start answering in the next sheet)
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The Answer is 21 bits Explaination The largest possible number of packets that could be genera... View full answer
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