Consider the following code fragment working with lists as defined in class let 1st1= ... //...

 

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Consider the following code fragment working with lists as defined in class let 1st1= ... // create a list with 3 elements const concat= (11, 12) 1st1= concat(concat(1st1, // end of the code fragment 11.isEmpty? 12: node(11. head(), concat(11. tail(), 12)); 1st1), 1st1) How many list nodes (created with node()) are no longer accessible at the end of this code fragment? Consider the following code fragment working with lists as defined in class let 1st1= ... // create a list with 3 elements const concat= (11, 12) 1st1= concat(concat(1st1, // end of the code fragment 11.isEmpty? 12: node(11. head(), concat(11. tail(), 12)); 1st1), 1st1) How many list nodes (created with node()) are no longer accessible at the end of this code fragment?

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In the code fragment you provided you are recursively concatenating the li... View the full answer