Question $2$

Find the integral

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}ta{n}^{2}xse{c}^{6}xdx$

$\frac{1}{7}ta{n}^{7}x+\frac{2}{5}ta{n}^{5}x-\frac{1}{3}ta{n}^{3}x+C$

$\frac{1}{7}ta{n}^{7}x+\frac{2}{5}ta{n}^{5}x+\frac{1}{3}ta{n}^{3}x+C$

$\frac{1}{5}ta{n}^{5}x+\frac{2}{3}ta{n}^{3}x-tanx+C$

$\frac{1}{5}ta{n}^{5}x+\frac{2}{3}ta{n}^{3}x-tanx+c$