Question: Question 2 In the following program, there is a call to the print_in_reverse function which has the following prototype: void print_in_reverse(float *a, int count); Using

Question 2 In the following program, there is a call to the print_in_reverse function which has the following prototype: void print_in_reverse(float *a, int count); Using pointers, write this function to print the array in reverse order. #include #define A_SIZE(A) sizeof(A)/sizeof(A[0]) void print_in_reverse(float a[], int count); int { main(void) float values[6] = { 12.1F, 22.2F, 32.3F, 42.4F, 52.5F, 62.6F }; printf("The array in reverse "); print_in_reverse(values, A_SIZE(values)); return 0; }

Question 3

The program below reads two integers. Then a function with the following prototype is called: void div_rem(int a, int b, int *divides, int *remains);This function is passed the two integers. It divides them (using integer division), and writes the answer over wherever divides points. Then it finds the remainder and writes it into where remains points. Thus for 20 and 3, 20 divided by 3 is 6, remainder 2. Implement the div_rem function. #include void div_rem(int a, int b, int *divides, int *remains); int { int int int main(void) a, b; div = 0; rem = 0; printf("enter two integers "); scanf("%i %i", &a, &b); div_rem(a, b, &div, &rem); printf("%i divided by %i = %i " "remainder %i ", a, b, div, rem); return 0; }

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