Question $2of6$

Let

$a_n=\frac{5n^2+14n}{3n^4-5n^2-19},b_n=\frac{5}{3n^2}\underset{n}{lim}\frac{a_n}{b_n}=$

Determine the convergence $or$ divergence $of{\displaystyle \underset{n=1}{\overset{}{}}}{a}_n.$

$(e)a_n$ converges $by$ the Limit Comparison Test because $\underset{n}{lim}{a}_{n}is$ fin

$2a_0$ converges $by$ the Limit Comparison Test because $\underset{?}{lim}\frac{a_0}{a_0}is$ Anit