Question $2$

The machine shown is designed as an overload protection device which releases the load when it exceeds a predetermined value $T.$ A soft metal shear pin $S$ is inserted in a hole in the lower half and is acted on by the upper half. When the total force on the pin exceeds its strength, it will break. The two halves then rotate about A under the action of the tensions in $BD$ and $CD,$ as shown in the second sketch, and rollers $E$ and $F$ release the eye bolt. Betermine themaximum corresponding force$-$on the hinge$-$pin$-4.$ Hint: Symmetry allows us to simplify this problem in a couple ways.

In Question $2$ of the homework, the symmetry of the machine allows what simplifications to be made?

The forces at point $E$ and $F$ are each equal to $T$

The forces at point E and F are each equal to $\frac{T}{2cos}$

The forces in members DB and DC are equivalent

The forces at point A have no y $-$components

The forces at point A have no $x-$components

The forces in members DB and DC are each equal to T$/2$

The forces at point S have no y $-$components

The forces at point $S$ have no $x-$components