Question: Question 20 In the following code, one line starts with #, what does this line do? #define PL 3.1416 int main() { chari: float radius,

 Question 20 In the following code, one line starts with #,
what does this line do? #define PL 3.1416 int main() { chari:
float radius, volume; cout > radius: > This is used to define

Question 20 In the following code, one line starts with #, what does this line do? #define PL 3.1416 int main() { chari: float radius, volume; cout > radius: > This is used to define a constant, whose value will not change. This is a comment aimed at a human reader. C++ ignore such comment That line is used to define a header file. That line is used to print to the console. Question 19 Consider this independent piece of code: oint outcome = 0.327; o outcome += 5; o outcome++; cout #include o using namespace std; o char a: o int main() { int zip1, zip2, zip3, zip4; o cout > zip1 >> zip2 >> zip3 >> zip4: o cout > o return 0; The compiler expect four entry while the user will enter three different numbers. The compiler expect three entries while the user want to enter four values. Nothing is wrong with this code. This code will not compile

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