Question: Question 21 (1 point) Saved A quality manager collected 25 samples of Honey-Nut Oatmeal packages from the production line, with each sample consist of 60

Question 21 (1 point) Saved A quality manager

Question 21 (1 point) Saved A quality manager collected 25 samples of Honey-Nut Oatmeal packages from the production line, with each sample consist of 60 packages of oatmeal. The average weight of a package among all samples has been calculated as 16.0 ounces. The quality standard requires that the weight of each package should be within the range 16.01.0 ounces. However, among all collected packages, there is an overall average fraction of 8% packages that fails to meet the requirement. The manager hopes to develop a control chart to monitor the fraction of packages in each sample that do not meet the quality standard. With a confidence level of 95.45%, what is the upper control limit of the control chart? Note: 1. Round your final answer to two decimal places. Do not round the intermediate numbers. 2. In case you get a percentage as the answer, convert it to a decimal number. For example, if your answer is 15.123%, convert it to 0.15123 and then round it to 0.15. Question 21 (1 point) Saved A quality manager collected 25 samples of Honey-Nut Oatmeal packages from the production line, with each sample consist of 60 packages of oatmeal. The average weight of a package among all samples has been calculated as 16.0 ounces. The quality standard requires that the weight of each package should be within the range 16.01.0 ounces. However, among all collected packages, there is an overall average fraction of 8% packages that fails to meet the requirement. The manager hopes to develop a control chart to monitor the fraction of packages in each sample that do not meet the quality standard. With a confidence level of 95.45%, what is the upper control limit of the control chart? Note: 1. Round your final answer to two decimal places. Do not round the intermediate numbers. 2. In case you get a percentage as the answer, convert it to a decimal number. For example, if your answer is 15.123%, convert it to 0.15123 and then round it to 0.15

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