. Question 23 Test the claim that on average, heights (in feet) of oak trees in a forest are more than heights of pine trees. Use a = 0.01. It is known that tree heights follow a normal distribution. The table below shows the results of two random samples. Type n S Oaks 15 85.2 17.1 Pines 22 79.2 16.8 1. The fact that heights are known to be normally distributed is important in this test because: O both standard deviations are less than thirty O both sample sizes are less than thirty O this is a Z-test this is a T-test The hypotheses are: O Ho: PI P2 O Ho: p1 2 P2; Ha : p1 M2 O Ho: p1 = p2; Ha : p1 # p22. This is a O right left two tailed test and the distribution used is O Z since testing two proportions O Z since both o values are known O T since both o values are not known The Degrees of Freedom (use the simple estimate discussed in the notes, not the messy formula) are O 15 ON/A; this is a Z-test O 14 3. The STS (round to 3 decimals) is: The P-value (round to 4 decimals) is: 4. The decision at a = 0.01 is: O Do not reject Ho since P o O Reject Ho since P a O Reject Ho since P > oxThe conclusion is: '33:? There is sufficient evidence to conclude that on average, oak tree heights are not more than pine tree heights '3' There is insufficient evidence to concLude that on average, oak tree heights are more than pine tree heights '13:} There is insufficient evidence to concLude that on average, oak tree heights are not more than pine tree heights '53:} There is sufficient evidence to concLude that on average, oak tree heights are more than pine tree heights