Question: QUESTION 26 , , s for waiting customers. Previous records indicate customers waiting. Y. is as follows. Y 0 1 2 3 4 5

 QUESTION 26 " , , s for waiting customers. Previous records

QUESTION 26 " , , s for waiting customers. Previous records indicate customers waiting. Y. is as follows. Y 0 1 2 3 4 5 P(Y=y) 0.421 0.162 0.133 0.114 0.094 0.076 What is the probability that exactly two customers are waiting? What is the probability that more than two customers are waiting? What is the probability that at most two customers are waiting? What is the probability that at least two customers are waiting? Find P(0 s Y

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