Question $3(1$ point$)$

A calculator will NOT $be$ available for this question.

For all $x$ such that $\frac{sin(2x)}{sinx}-\frac{cos(2x)}{cosx}\frac{1}{sinx}-\frac{1}{cosx}$

$2cosx-2sinx$

$sinx-cosx$

$0$

$\frac{1}{cosx}0,$ which $of$ the following $is$

equivalent $to\frac{sin(2x)}{sinx}-\frac{cos(2x)}{cosx}?$

$\frac{1}{sinx}-\frac{1}{cosx}$

$2cosx-2sinx$

$sinx-cosx$

$0$

$\frac{1}{cosx}$