Question $3$

$1$ pts

In a simple two$-$band QMF bank, the low band filter is $H(z)=0\mathrm{.}5+0\mathrm{.}5z^{-1}.$ The transfer function of the high band filter is

$H(z)=1-0\mathrm{.}5z^{-1}$

$H(z)=0\mathrm{.}5-0\mathrm{.}5z^{-1}$

$H(z)=\frac{1}{0\mathrm{.}5+0\mathrm{.}5z^{-1}}$

$H(z)=\frac{1}{1+0\mathrm{.}5z^{-1}}$

None of the above