Question: Question 3 : ( 3 0 marks ) a ) ( 1 8 marks ) A railroad horizontal curve of length 8 0 0 meters

Question 3: (30 marks)
a)(18 marks) A railroad horizontal curve of length 800 meters and length of spiral is 105 meters and had an equilibrium elevation of 120mm. Also given the station 125+09.50m(20 meter stations) has same elevation for both rails equal to 60.99m, if the Tangent to Spiral (TS) is at station "x" and the grade from Station 125+09.5 until Spiral Tangent (ST) station is "Y"(See values of "x" and "Y" for various students' groups in the table below), determine
i)(6 marks) The elevation of inner and outer rail at station 133+05.50
ii)(6 marks) The elevation of inner and outer rail at station 148+19.51
iii)(6 marks) The elevation of inner and outer rail at station 178+10.00
\table[[\table[[Students fifth and seventh numbers],[from the left (example of number],[in red and bold: 1161840 the],[number is 80 in this example)]],\table[[Tangent to Spiral (TS)],[Station "X"]],\table[[The grade of the],[entire rail section],[(from station],[125+09.50 to Spiral],[Tangent (ST)"Y"]]],[A= Between 00 and 24(inclusive),130+11.50,-0.50%
Question 3 : ( 3 0 marks ) a ) ( 1 8 marks ) A

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Civil Engineering Questions!