Question 3 (3 points) [3] Given dictionaries, d1 and d2, create a new dictionary d3 with the following properties: (a) For each entry (a, b) in d1, if a is not a key of d2, then add (a,b) to d3; (b) For each entry (a, b) in d2, if a is not a key of d1 then add (a,b) to d3. For example: if d1={2:3, 8:19, 6:4, 5:12} and d2={2:5, 4:3, 3:9} then d3={8: 19, 6:4, 5: 12, 4:3, 3:9). [You can write a function, or plain code (i.e., without a function), up to you.] AM