Question 3 A light source is defined with ambient property (0.2, 0.2, 0.2) and both diffuse and specular properties set to Not yet white. For each of the three cases (a),(b),(c) given below, compute the ambient, diffuse and specular reflections answered from the surface. Assume that for all the cases, the material's specular property is set to white and that the Marked out of Phong's constant (shininess) has a value 3. Please note that the material's ambient colour is same as the 6.00 diffuse colour. In the following table, 0 denotes the angle between the light source vector and normal vector, Flag question and 4 the angle between the reflection vector and the view vector. In your answer, please include the numerical expression used for obtaining each color value : Example, (a) Ambient reflection = (0, 0, 1)*(0, 1, 1) = (0, 0, 1). (a) (b) (c) Material's Ambient Yellow Cyan Blue and Diffuse Color e 100 30 0 90 0 60