Question $3$

Find $\frac{dy}{dx}$ if $y=\sqrt[7]{x^3-5x^{4}7x}.$

$\frac{dy}{dx}=\frac{1}{7}(3x^2-20x^{3}7)(-\frac{6}{7})$

$\frac{dy}{dx}=0$

$\frac{dy}{dx}=\frac{1}{7}(x^3-5x^{4}7x)(-\frac{1}{7})$