Question $3$

If $f(x)={\displaystyle \underset{x}{\overset{5}{}}}cos(t^3-2)dt,$ then $f^{\text{'}}(x)=$

$-5cos(x^3-2)$

$sin(x^3-2)$

$-cos(x^3-2)$

$cos(x^3-2)$

$-sin(x^3-2)$