# Question 3:
	# Modify the function such that it works according to the description below:
	#
	# This function assumes dictX is a dictionary with the following structure:
	# the key is always a string and the value is always an int. Here is a
	# sample dictionary: {'john': 93, 'jane':87, 'kramer': 53} and it has 3 entries.
	#
	# Each key-value pair in a dictionary is considered to be an entry.
	#
	# This function returns the number of entries where the key has one letter
	# in common with your 7 letter unique word AND the value has one digit
	# in common with your 5 digit number. The letters can be in either upper
	# or lower case.
	#
	# So, for Jane:
	# question3({'john': 93, 'jane':87, 'kramer': 53})
	# should return 2 (the first and third entry matches)
	#
	# question3({'ann': 93, 'pat':87, 'kramer': 987})
	# should return 0 (no entry matches conditions)
	def question3(dictX):
	return 0 # Do not use python lambdas # Do not use maps/filters #Do not import any other libraries - not even built-in ones, such as math # Change this to your specific 7 letter unique word MY_WORD = 'ORCHIDS' # Change this to your specific 5 digit unique number MY_NUM = 12345