QUESTION 3. Submit all steps, code, script, solutions, plots, etc. [Mark: 3.5] kW electric mixer with a 0.2, m diameter impeller is used to mix 1000 kg liquid mixture. The change in turbulent kinetic energy (TKE) per unit mass can be expressed as d(3u2/2)/dt = TKE production rate / mass - TKE dissipation rate / mass. If all energy input to the electric mixer goes into mixing, we have TKE production rate = 3, kW = 3,000 W. 1 The dissipation or decay rate of TKE may be estimated as TKE dissipation rate = u/L. The size of the mixing eddies may be assumed to scale with the impeller diameter. Doing so, we get TKE dissipation rate u/0.2. Therefore, for 1000 kg of liquid, the energy balance is 2 Differentiating 3u2/2 gives This can be rearranged into d(3u2/2)/dt = 0.03 - u/(20). 3u du/dt = 0.03, - u/(2,0). {3u/[0.03a, -u/(2,0)]} du = dt. Estimate the time it takes to reach 70% of the maximum mixing intensity. Here, , , are the smallest, second smallest, and third smallest non-zero digits, respectively, of your student ID. E.g., ID = 110 985 247 gives a = 1, = 2, and = 4, i.e., {3u/[0.031 - u/(220)]} du = dt 2