QUESTION 4 15 points Save Answer A quality inspector took five samples, each with five observations of the length of time in minutes) for glue to dry. The analyst computed the mean of each sample as, 11.93, 12.17, 12.74, 12.29 and 12.12. Use this information and alpha risk of 0.08 to obtain control limits for means of future times. It is known from previous experience that the standard deviation of the process is 1.07 minute. STEP 1: Provide control limits for the mean chart: LCL | CL- UCL- STEP 2: The inspector continued to periodically sample the process and recorded values for six samples as shown in the following table. SAMPLE Observation 1 2 3 3 4 5 6 1 12.84 9.96 10.44 9.96 10.44 9.96 2 11.52 12.24 10.80 11.16 14.04 12.24 3 13.20 12.00 12.48 11.04 13.20 11.52 14.40 4 9.00 9.00 10.80 10.80 13.20 5 11.78 12.84 12.12 10.32 10.32 12.12 Enter the values you plot in mean chart, starting from the first sample: Sample 1: Sample 2: Sample 3: Sample 4: Sample 5: Sample 6