Question $4(7$ points$)$

How much heat must be added to $0\mathrm{.}35$ kg of aluminum to change it from a solid at $108C$ to a liquid at $660C($its melting point$)?$ The latent heat of fusion for aluminum is $L_f=4\mathrm{.}0{10}^5\frac{J}{k}g$ and the specific heat capacity is $c=9\mathrm{.}00{10}^2\frac{J}{k}gC.$

$Q_{\text{h}\text{e}\text{a}\text{t}}=mcT=mc(660C-108C)$

$Q_{\text{m}\text{e}\text{l}\text{t}}=m{L}_f$

$Q_{\text{t}\text{o}\text{t}\text{a}\text{l}}=Q_{\text{h}\text{e}\text{a}\text{t}}+Q_{\text{m}\text{e}\text{l}\text{t}}$

Round your answer to the nearest $10$: for example, $222,430.$

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