Question 4: Draw a symbol table for the following code using a separate chaining approach. Assume the size of the table is 10. Show how the table evolves at each statement. You can calculate the hash value using the hash() function provided underneath:

1. public class CC {

2. int a;

3. public void m(int a) {

4. char c='B';

5. {

6. double d=0.0;

7. }

8. }

9. } //end CC class public int hash( String k ) { int value = 0; for( int i=0; i

public int hash( String k ) {

int value = 0;

for( int i=0; i

value = value + (int)k.charAt( i );

}

return value % 10;

} //end HASH() function

Hint: A-Z ranges 65-90 and a-z ranges 97-122. Hence identifier A will have has value 5, B will have 6, and similarly identifier AB will have 1 and so on.