Question $4$: fine$\_$per$\_$plates$()$

Starting in $2004$ Michigan moved to issuing plates with the format of ABC$1234.$ That got me thinking, how many vanity plate holders there are in our

dataset? Count for me the number of Michigan vehicles with plates in the following formats that have received a ticket:

ABC$1234$

ABC$123$

$123$ABC

Vanity Plates $($i$.$e$.$ anything other than the aforementioned formats, including missing or NaN values$)$

Complete the function fine$\_$per$\_$plates$()$ returning a dictionary. The dictinary should be formatted as follows:

$plate{s}_d$ict $=\{$ ABC$1234$: $th{e}_{n}umbe{r}_o{f}_v$ehicles,

ABC$123$: $th{e}_{n}umbe{r}_o{f}_v$ehicles,

$123$ABC: $th{e}_{n}umbe{r}_o{f}_v$ehicles

vanity: $th{e}_{n}umbe{r}_o{f}_v$ehicles $\}$ code:import pandas as pd

import numpy as np

import re

def fine$\_$per$\_$plates$()$:

plates$\_$dict $=\{"$ABC$1234"$: $0,$ "ABC$123"$: $0,"123$ABC": $0,$ "vanity": $0\}$

data $=$ pd$.$DataFrame$(\{"$Plate$"$: $["$ABC$1234","123","123$ABC", $"$XYZ$567",$ "VANITY"$]\})$

abc$1234\_$pattern $=$ re$.$compile$($r$\text{'}^[$A$-$Z$]\{3\}\backslash$d$\{4\}$$$\text{'})$

abc$123\_$pattern $=$ re$.$compile$($r$\text{'}^[$A$-$Z$]\{3\}\backslash$d$\{3\}$$$\text{'})$

a$123$abc$\_$pattern $=$ re$.$compile$($r$\text{'}^\backslash$d$\{3\}[$A$-$Z$]\{3\}$$$\text{'})$

for plate in data$["$Plate$"]$:

if abc$1234\_$pattern.match$($plate$)$:

plates$\_$dict$["$ABC$1234"]+=1$

elif abc$123\_$pattern.match$($plate$)$:

plates$\_$dict$["$ABC$123"]+=1$

elif a$123$abc$\_$pattern.match$($plate$)$:

plates$\_$dict$["123$ABC"$]+=1$

else:

plates$\_$dict$["$vanity$"]+=1$

return plates$\_$dict

# Test the function

print$($fine$\_$per$\_$plates$())$ the problem is : TypeError Traceback $($most recent call last$)$

Cell In$[18],$ line $1$

$---->1$ assert len$($fine$\_$per$\_$plates$())==4,$ "Return a dictionary with four items."

TypeError: fine$\_$per$\_$plates$()$ missing $1$ required positional argument: 'data$\_$path'