Question $5(1$ point$)$

At $0C$ and an absolute pressure of $611\frac{N}{m}2,305g$ of water, $305g$ of water vapor, and $305g$ of ice are in equilibrium in a sealed thermal container. Determine how much energy in calories should be removed to freeze all the water and vapor.

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Note: $611\frac{N}{m^{{?}^{{?}^{?}}}}2$ is the vapor pressure of water at $0$deg C$.($Table $1\mathrm{.}1)$

E$1$ is energy required to change water to ice $=$ mass $x$ heat of fusion

E$2$ is energy required to change vapor to ice $=$ mass vapor $x$ heat of vaporization $+$ mass water $x$ heat of fusion