Question $5$

Evaluate ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{1}{(x^2-a^4{b}^4)}dx$

$\frac{1}{2a^2{b}^2}ln|x-a^2{b}^2|-\frac{1}{2a^2{b}^2}ln|x+a^2{b}^2|+C$

$-\frac{1}{2}ln|x-a^2{b}^2|+\frac{1}{2}ln|x+a^2{b}^2|+C$

$\frac{1}{2ab}ln|x-a^2{b}^2|+\frac{1}{2ab}ln|x+a^2{b}^2|+C$

$-\frac{1}{2}ln|x-a^2{b}^2|-\frac{1}{2}ln|x+a^2{b}^2|+C$