Question $6(1$ point$)$

The regular expression for the epsilon$-$NFA is:

$(0+1{)}^{**}01(0+1{)}^{**}$

$(0{)}^{**}01(0+1{)}^{**}$

$(0+1{)}^{**}01(0+1)$

$(0+1)01(0+1{)}^{**}$