Question 6 (6 marks) A wire is placed in a uniform magnetic field shown below B The length of the wire in the field is L = 0.4 m. The wire is placed at an angle 0 to the magnetic field and the magnetic flux density is B = 0.8 T. When the current in the wire I = 0.5 A, the net force on the wire is F = 0.6 N. a) Calculate the angle 0. [2] b) What would happen to the net force on the wire if the current carried by the wire doubled? Assume 0 and the magnetic flux density are kept constant. [1] A positive charge q now enters the field B (still with B = 0.8 T) from below at a speed of v = 2 x 10' m s" as shown in the diagram below. The charge experiences a force of 2.88 x 10"7 N. B c) Determine the magnitude of the charge and state the direction that the charge is forced as it enters the field. [1] Page 6 of 7 PHYSICS 102 Two charges Q1 = 1.602 x 10-19 C and Q2 = -1.602 x 10-19 C are placed 53 pm apart (1 pm = 10 x 10"12 m). Q2 53 pm d) Calculate the Coulomb force between the two charges. [1] e) If we increase charge Q2 to -5.126 x 10-18 C. How many electrons would this correspond to? [1]