QUESTION $6[6]$ Please carefully read the following scenario: A

publishing house publishes three weeks magazines$-$Daily Life,

Agriculture Today, and Surf's Up$.$ Publication of one issue of each

of the magazines requires the following amounts of production time

and paper: Production $($hr$.)$ Paper $($Ib$.)$ Daily Life $0\mathrm{.}010\mathrm{.}2$

Agriculture Today $0\mathrm{.}030\mathrm{.}5$ Surf's Upo $0\mathrm{.}020\mathrm{.}3$ Each week the

publisher has available $120$ hours of production time and $3,000$

pounds of papers. Total circulation for all three magazines must

exceed $5,000$ issues per week if the company is to keep the

advertisers. The selling price per issue is $ $2\mathrm{.}25$ for Daily Life,

$$4\mathrm{.}00$ for Agriculture Today, and $$1\mathrm{.}50$ for Surf's Up$.$ Based on past

sales, the publisher knows that the maximum weekly demand for Daily

Life is $3,000$ issues; for Agriculture Today, $2,000$ issues; and

Surf's Up$.6,000$ issues. The production manager wants to know the

number of issue of each magazine to produce weekly in order to

maximize total sales revenue.$[6]$ The total number of decision variables in this problem

is$[7]$ The total number of constraints in this problem,

including non$-$negativity constraints is$[8]$ Given the constraints in this problem the maximum

profit is:$[9]$ At the profit$-$maximizing level of output the total quantity

of paper leftover $($not used$)$ every week is:$[10]$ At profit$-$maximizing level of output the total number of

units produced of all three magazines combined is:$$N