Question $6$

By inspection, the transfer function of the Common Source Amplifier in the figure where $0$ is:

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a$.$

$\frac{-g_m*(R_D)}{1+s{C}_L(R_D)}\frac{r_{}}{r_{}+R_D}$

b$.$

$\frac{-g_m*(R_{D}uarruarr{r}_o)}{1+s{C}_L(R_{D}uarruarr{r}_o)}$

c$.$

$\frac{-g_m*R_D}{1+s{C}_L{R}_D}$

d$.$

$\frac{g_m*(R_{D}uarruarr{r}_o)}{1+s{C}_L(R_{D}uarruarr{r}_o)}$