Question 6: (ILO's 3) (6 points) The following table represent small project to be constructed, answer the questions below. Assume indirect cost equal to 250 s/day Activity Predecessor Normal Crash Time (days) Cost (3) Time (days) Cost (S) A 8 840 6 1120 B 16 1600 12 2240 2 12 2000 8 2400 D A 2 18 2160 14 2400 E C, B i 8 2000 2 4400 F CB3 10 600 8 960 G 6 600 6 600 H DF 14 2400 3000 OR 1. The additional direct cost of deereasing project's duration 6 days is. 880 190 * 2. The amount of indirect cost saving when decreasing project by 5 days is 1250 3. The minimum duration of project after crashing is 1938 4. The total cost of project after decreasing project duration by 5 days is 12840 5. The total cost of project for all normal solution is 1712023200 6. The total direct cost of the project for the all crash solution is - 17120 12 3210