Question: Question 7: a) Let L 3 = {1 n 0 k 1 4n | n 0, k > 0}. Prove thatd there is no DFA
Question 7:
a) Let L3 = {1n0k14n | n 0, k > 0}. Prove thatd there is no DFA M3 for L3 such that L(M3) = L3
b) Let L4 = {a, b} \ {wawR | w is any string over {a, b}} be a language over = {a, b}. Prove that there is no DFA M4 such that L(M4 ) = L4. Your proof should be short and not use the Pumping Lemma.
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