Question 7 The three simultaneous congruences X= 0 (nod4) x = 0 (mod 8) x = 0 (mod 16) are equivalent to simply writing x = 0 (mod 16). cannot be solved since 4, 8, and 16 are not (pairwise) relatively prime. are equivalent to simply writing x = 0 (mod 8). are equivalent to simply writing x = 0 (mod 4). cannot be solved since x^(-1) does not exist, since O has no inverse. A Moving to the next question prevents changes to this