Question $8$

$15$ points

For the circuit in the below figure, C$1=10uF,C2=82uF,C3=68uC,R1=6\mathrm{.}2$Ohm,$R2=2$Ohm,$RL=1\mathrm{.}3$Ohm,$|V1|=90V$ phase $50$ degrees, $|||$ V$2|||=8V$ phase $90$ degrees, and $f=6kHz.$ After using Node analysis, the set of second$-$order equations written in standard form is:

$(0\mathrm{.}1613+j3\mathrm{.}4683)VA+(-j3\mathrm{.}0913)VB=(-25\mathrm{.}9913+j21\mathrm{.}8093)-($Equation for Node$-$A$)$

$(-$ j$3\mathrm{.}0913)$ VA $+(1\mathrm{.}2057+$ j$3\mathrm{.}3031)$ VB $=(+$ j$4)-->($Equation for Node$-$B$)$

Solve the equations to determine which of the following is true?

Round up your answer to exactly two decimal points.

Warning: selecting a wrong answer takes marks away.

$|VB|=22\mathrm{.}71V$

$|VA|=50\mathrm{.}17V$

None of the answers

$|VA|=25\mathrm{.}96V$

Angle of $VA=123\mathrm{.}82$ degrees

Angle of $VA=97\mathrm{.}34$ degrees

$|VB|=18\mathrm{.}24V$

Question $8$

$15$ points

For the circuit in the below figure, C$1=10uF,C2=82uF,C3=68uC,R1=6\mathrm{.}2$Ohm,$R2=2$Ohm,$RL=1\mathrm{.}3$Ohm,$|V1|=90V$ phase $50$ degrees, $|||$ V$2|||=8V$ phase $90$ degrees, and $f=6kHz.$ After using Node analysis, the set of second$-$order equations written in standard form is:

$(0\mathrm{.}1613+j3\mathrm{.}4683)VA+(-j3\mathrm{.}0913)VB=(-25\mathrm{.}9913+j21\mathrm{.}8093)-($Equation for Node$-$A$)$

$(-$ j$3\mathrm{.}0913)$ VA $+(1\mathrm{.}2057+$ j$3\mathrm{.}3031)$ VB $=(+$ j$4)-->($Equation for Node$-$B$)$

Solve the equations to determine which of the following is true?

Round up your answer to exactly two decimal points.

Warning: selecting a wrong answer takes marks away.

$|VB|=22\mathrm{.}71V$

$|VA|=50\mathrm{.}17V$

None of the answers

$|VA|=25\mathrm{.}96V$

Angle of $VA=123\mathrm{.}82$ degrees

Angle of $VA=97\mathrm{.}34$ degrees

$|VB|=18\mathrm{.}24V$