QUESTION $8*1$ POINT

What $is{r}^{\text{'}}(x)$ when $r(x)=lo{g}_8(\frac{5x^2+5x+1}{x^6{8}^x})?$

Select the correct answer below:

$r^{\text{'}}(x)=\frac{10x+5}{(5x^2+5x+1)ln8}-\frac{6}{xln8}-1$

$r^{\text{'}}(x)=\frac{10x+5}{5x^2+5x+1}-\frac{6}{x}-1$

$r^{\text{'}}(x)=\frac{x^6(1)ln8}{5x^2+5x+1}$

$r^{\text{'}}(x)=\frac{1}{(5x^2+5x+1)ln8}-\frac{6}{xln8}-1$

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