QUESTION $8$

You are hacking into a remote MIPS CPU and pause the machine. At the moment, registers $$1-$ $$10$ all have value $7,$$$11-$$$20$ all have value $-1,$ all the other registers have value $0,$ and all the data memory have value $-5.$

From the instruction memory, all you can know are the following: at address $000000020$ is $00120602a,$ at $000000024$ is $015800003,$ at $000000028$ is $0ac0a2004.$ Now, PC $=000000020,$ and you allowed the

program to execute... Write out what these instructions are, and explain the expected behavior. Select all the correct options from below and explain why each is correct or not.

The instruction at $000000020$ will be executed and change the value of $$12.$

The instruction at $000000020$ will be executed, but will not change the value of any register.

The instruction at $000000020$ will change PC to $000000028.$

The instruction at $000000024$ will change PC to $000000028.$

The instruction at $000000024$ will change PC to $000000034.$

The instruction at $000000024$ will be executed and will change the value of $$11.$

The instruction at $000000028$ will be executed and will change the value of $$10.$

The instruction at $000000028$ will not be executed.

The instruction at $000000028$ will be executed and update PC to $00000002c.$

None of the above is correct.

Please explain all and show work