Question: Question 9 0 . 4 pts dx Oy = x 2 en - xe + Cx Oy = x 2 ea - 2 xe

Question 9
0.4 pts
dx
Oy = x2en - xe + Cx
Oy = x2ea -2xe"+2e+ C
O y = xea +Cx
O y = xe -2ea +2x-le"+ Cx-1
find the general solution to the given linear differential equation.

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