Question $9(1$ point$)$

Let $f(x)=\frac{\sqrt[\phantom{2}]{x1}}{x^{3}x1}.$ What is the numerator of the derivative $f^{\text{'}}(x)?$

$\frac{1}{2}(\sqrt[\phantom{2}]{x1})(x^{3}x1)-(3x^{2}1)\sqrt[\phantom{2}]{x1}$

$(3x^{2}1)\sqrt[\phantom{2}]{x1}-\frac{1}{2(\sqrt[\phantom{2}]{x1})}(x^{3}x1)$

$\frac{\frac{1}{2}(\sqrt[\phantom{2}]{x1})(x^{3}x1)-(3x^{2}1)\sqrt[\phantom{2}]{x1}}{(x^{3}x1{)}^2}$

$\frac{1}{2(\sqrt[\phantom{2}]{x1})}(x^{3}x1)-(3x^{2}1)\sqrt[\phantom{2}]{x1}$