Question: Question 9 1 pts 2(e). Based on this interval, would X getting less than half of the vote in Florida have been surprising? If X

 Question 9 1 pts 2(e). Based on this interval, would Xgetting less than half of the vote in Florida have been surprising?If X got more than half of the vote in Florida, would

it have been surprising? Explain briefly. Edit View Insert Format Tools Table12pt Paragraph * B I U A 2 Ty ... p (10 words > >Question 6 1 pts 2(b). What is the standard

Question 9 1 pts 2(e). Based on this interval, would X getting less than half of the vote in Florida have been surprising? If X got more than half of the vote in Florida, would it have been surprising? Explain briefly. Edit View Insert Format Tools Table 12pt Paragraph * B I U A 2 Ty ... p (1 0 words > >Question 6 1 pts 2(b). What is the standard error for the sampling distribution of the sample proportion in this case? Round your answer to 2 decimal places. 0.02087 Question 7 0.5 pts 2(c). What is the margin of error for a 95% confidence level? Round your answer to 2 decimal places. m = 0.0400 Question 8 0.5 pts 2(d). Give the lower and upper limits of the 95% confidence interval for the population proportion, p, of voters who planned to vote for X based on the sample. Round your answers to 2 decimal places.Question 5 1 pts 2. In the November 2023 election, X received 49% of the votes cast in Florida (the candidate, Y, received 45%). Many news organizations conduct surveys before elections to try to predict the winner. Suppose a survey was conducted in Florida shortly before the election such that we can assume that the true proportion of the population who planned to vote for X was 49%. The pollsters surveyed 600 likely voters and found that 283 of them planned to vote for X. Answer parts (a) through (e). 2(a). What were the population and sample proportions? Give your answers as decimals. If needed round values to 2 decimal places. Population proportion, p : 0.49 Sample proportion, p : 0.4716

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