Question $9$

${\displaystyle \underset{-5}{\overset{5}{}}}{\displaystyle \underset{-3}{\overset{3}{}}}dxdy={\displaystyle \underset{-3}{\overset{3}{}}}{\displaystyle \underset{-5}{\overset{5}{}}}dydx=$

${\displaystyle \underset{-3}{\overset{3}{}}}{\displaystyle \underset{-5}{\overset{x}{}}}dydx{\displaystyle \underset{-5}{\overset{5}{}}}{\displaystyle \underset{-3}{\overset{3}{}}}dydx$

${\displaystyle \underset{-3}{\overset{3}{}}}{\displaystyle \underset{\frac{45}{3}}{\overset{5}{}}}dydx{\displaystyle \underset{-5}{\overset{5}{}}}{\displaystyle \underset{\frac{2y}{3}}{\overset{3}{}}}dxdy$

${\displaystyle \underset{-5}{\overset{5}{}}}{\displaystyle \underset{-3}{\overset{\frac{-3y}{5}}{}}}dxdy{\displaystyle \underset{-3}{\overset{3}{}}}{\displaystyle \underset{\frac{-3}{5}}{\overset{5}{}}}dydx$

${\displaystyle \underset{-3}{\overset{3}{}}}{\displaystyle \underset{-3}{\overset{\frac{2}{3}}{}}}dxdy{\displaystyle \underset{-5}{\overset{5}{}}}{\displaystyle \underset{-5}{\overset{\frac{2}{3}}{}}}dydx$

${\displaystyle \underset{-3}{\overset{3}{}}}{\displaystyle \underset{\frac{5}{3}}{\overset{5}{}}}dydx{\displaystyle \underset{-5}{\overset{5}{}}}{\displaystyle \underset{-3}{\overset{\frac{2y}{5}}{}}}dxdy$

${\displaystyle \underset{-5}{\overset{5}{}}}{\displaystyle \underset{-3}{\overset{\frac{3y}{5}}{}}}dxdy{\displaystyle \underset{-3}{\overset{3}{}}}{\displaystyle \underset{-5}{\overset{\frac{2y}{3}}{}}}dydx$