Question A

Small steel balls fall from rest through the opening at A at the steady rate of 4 per second. Find the vertical separation h of two consecutive balls when the lower one has dropped 1.1 meters. Neglect air resistance. The 220000-lb space-shuttle orbiter touches down at about 231 mi/hr. At 206 mi/hr its drag parachute deploys. At 47 mi/hr, the chute is jettisoned from the orbiter. If the deceleration in feet per second squared during the time that the chute is deployed is -0.000240v2 (speed v in feet per second), determine the corresponding distance s traveled by the orbiter. Assume no braking from its wheel brakes. Answer: S = i ftIn traveling a distance of 2.3 km between points A and D, a car is driven at 89 km/h from A to B for t seconds and 52 km/h from C to D also for t seconds. If the brakes are applied for 5.9 seconds between B and C to give the car a uniform deceleration, calculate t and the distances between A and B. 89 km/h 52 km/h B D 2.3 km Answers: t = S S= i km