QUESTION

ANSWER

We know that the velocity $(v(t))$ is the derivative of position $(x(t))$ with respect to time, meaning $v(t)=\frac{it}{d}.$ Given that, what do we get if we integrate the velocity of an object from $t-1$ to $t-4,$ meaning ${\displaystyle \underset{t=1}{\overset{t=1}{}}}v(t)dt?$

The change in the object's velocity between $t-1$ and $t-4$

The change in the object's position between $t-1$ and $t-4$

The sum of the object's position at $t-1$ and its position at $t-4$

The object's total position at $t-4$

IDON'TKNOWYET