Question: Array Resizing

Ex1.

Before calling the function

Array = [10,2,3,15,6]

Size = 5

After calling the function

Array=[2,3,6]

size=3

Ex2.

Before calling the function

Array = [11,2,3,16,6,17,18]

Size = 7

After calling the function

Array=[11,2,3,16,6,17,18]

size=7

Specification:

• Inputs The function will receive two arguments:

1.the array as reference to a pointer

2.the length as reference to an integer

• Return void
• Function should not return anything

• Function prototype
• void removeDivByFive(/*fill this with pointer reference to the array, int reference to the length */)

Expectations:

1. Do not modify the function prototype
2. The function should with a new array dynamically and copy the numbers not divisible by 5 from the old array.
3. Size of the new array should be exactly the number of elements non-divisible by five.
4. There must not be any memory leaks
5. Function must use reference to pointer for array and reference to integer for the length
6. Code should compile without any errors

arr.cpp

in c++

#include

using namespace std;

void removeDivByFive(/*fill this with pointer reference to the array, int reference to the length */)

{

}

int main(int argc, char* argv[])

{

int size = 5;

int* arr = new int[size];

arr[0] = 10;

arr[1] = 2;

arr[2] = 3;

arr[3] = 15;

arr[4] = 6;

cout<<"before calling the function"<

cout<<"size:"<

cout<<"arr:";

for(int i=0;i

{

cout<

}

cout<

removeDivByFive(arr,size);

cout<<"after calling the function"<

cout<<"size:"<

cout<<"arr:";

for(int i=0;i

{

cout<

}

cout<

}