question below, please answer correctly:

point (1, 0, 2, -1). Let f(w, x, y, z) = (2w + xz, y x2 + 2w -z, wax + 3y). Compute the Jacobian matrix [Jf(w, x, y, z)] at an arbitrary point (w, x, y, z) and at the 2 Z 0 X [Jf (w, x, y, z) ] = 2 2y^2x 2x^2y -1 2xw W^2 3 0 2 -1 0 [Jf(1, 0, 2, -1)] = 2 0 0 -1 0 3 0 2 Now consider f (1, 0, 2, -1) = 3 . If we change the input point (1, 0, 2, -1) by h = (-0.1, -0.1, 0.1, 0.1), then the approximate change 6 0.21 1.89 in the function (as estimated by the derivative) is 0.3001 , and the approximate value of the function is f(0.9, -0.1, 2.1, -0.9) ~ 2.7441 -0.299 6.219