Question: QUESTION : Design F = ( 1 , 2 , 5 , 7 , 8 , 1 0 , 1 5 ) using only one

QUESTION : Design F =(1,2,5,7,8,10,15) using only one of the options below:
a.8-to-1 MUX to get the full marks.
(the image is the answer)
Ive seen the given question and the answer youve provided for designing F =(1,2,5,7,8,10,15) using an 8-to-1 MUX, but Im having a hard time understanding the reasoning behind the final arrangement. Could you please break down the steps, like taking lecture-style notes, to explain how and why the solution was obtained?
Specifically, I want to understand:
How the original functions minterms translate to which inputs of the MUX should be high or low.
Why certain input lines of the MUX correspond to certain minterm indices.
How the select lines (W, Z, Y) are chosen and how the mapping from W, Z, Y to the inputs relates to the minterm numbers.
The logical process or algorithm for deciding what goes where on the MUX inputs and why that gives the correct output for all combinations.
In short, Im not just looking for the final wiring diagram. Id like a clear, step-by-step explanation of the thought process behind it, written as if it were organized classroom notes. Thanks!
QUESTION : Design F = ( 1 , 2 , 5 , 7 , 8 , 1 0 ,

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