Question I

$\frac{0}{1}$ pt $010026$

Detail

Find $y/$by $($a$)$ applying the Product Rule and $($b$)$ multiplying the factors to produce a sum of simpler terms to differentiate.

$y=(9-x^2)(x^3-8x-6)$

a$.$ Apply the Product Rule. Let $u=9-x^2$ and $v=x^3-8x-6.$

$($:$\frac{d}{dx}(uv)=(9-x^2)\}$

b$.$ Multiply the factors of the original expression, $u$ and $v,$ to produce a sum of simpler terms.

$y=$

Find $y$

$y^{\text{'}}=$