Question

If $r(x)=lo{g}_5(\frac{x^6{5}^2}{5x^{2}5}),$ find $r^{\text{'}}(x)$

Select the correct answer below:

$r^{\text{'}}(x)=\frac{6}{xln5}1-\frac{10x}{(5x^{2}5)ln5}$

$r^{\text{'}}(x)=\frac{5x^{2}5}{x^6(5)ln5}$

$r^{\text{'}}(x)=\frac{6}{xln5}\frac{x{5}^2-1}{5^{x}ln5}-\frac{10x}{(5x^{2}5)ln5}$

$r^{\text{'}}(x)=\frac{6}{x}1-\frac{10x}{5x^{2}5}$