Question L9: On a piece of graph paper draw a cross section of Boulder Creek at...

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Question L9: On a piece of graph paper draw a cross section of Boulder Creek at transect A. The water height is the same at each position, but the channel depth differs. See the figure below for an example of how to do this. Observation surface _NM=Lat 12345 dist. from bank water depth Note: Do questions 9-14 on the graph paper, take 24 in 2 in 48 in 72 in a photo of these questions when you're done and then attach them to the email separately from this document. 96 in 120 in Dist. from bank 3 in 5 in 2 in In Question L10: Use the cross section to compute the area (i.e. count the squares!) of the transect. Remember to use the scale you set while drawing the transect. See the example below for help. surface DOYILN 5 q 2 N Dist. from bank 12 12x1 = 12in - each tick an x axis = 24 - each tick on axis = 1 Question L13-L14: Repeat questions 9-12 for transect B. on y cout the shaded area Question L11: Convert the channel from in to ft. Remember, there are 12 inches in in a foot, so one foot squared is 144 in. Show your work. Question L12: Now calculate discharge. This is done by multiplying the cross-sectional area (in ft) by the velocity in ft/sec. Show your work. Question L15: Compare the discharges at location A and B. Are they the same? Do you expect them to be the same or different? Why? Question L16: Was the current velocity at location A, where the channel is narrower, faster or slower than B? Does this make sense? Explain why or why not. Question L9: On a piece of graph paper draw a cross section of Boulder Creek at transect A. The water height is the same at each position, but the channel depth differs. See the figure below for an example of how to do this. Observation surface _NM=Lat 12345 dist. from bank water depth Note: Do questions 9-14 on the graph paper, take 24 in 2 in 48 in 72 in a photo of these questions when you're done and then attach them to the email separately from this document. 96 in 120 in Dist. from bank 3 in 5 in 2 in In Question L10: Use the cross section to compute the area (i.e. count the squares!) of the transect. Remember to use the scale you set while drawing the transect. See the example below for help. surface DOYILN 5 q 2 N Dist. from bank 12 12x1 = 12in - each tick an x axis = 24 - each tick on axis = 1 Question L13-L14: Repeat questions 9-12 for transect B. on y cout the shaded area Question L11: Convert the channel from in to ft. Remember, there are 12 inches in in a foot, so one foot squared is 144 in. Show your work. Question L12: Now calculate discharge. This is done by multiplying the cross-sectional area (in ft) by the velocity in ft/sec. Show your work. Question L15: Compare the discharges at location A and B. Are they the same? Do you expect them to be the same or different? Why? Question L16: Was the current velocity at location A, where the channel is narrower, faster or slower than B? Does this make sense? Explain why or why not.

Answer rating: 100% (QA)

Certainly Lets tackle each part of this problem step by step Drawing the Cross Section Transect A On ... View the full answer