Question

Let $h(x)=\frac{f(x)}{g(x)},$ where $f(x)=3x^{2}2x-3$ and $g(x)=3x.$ What is $h^{\text{'}}(x)?$

Select the correct answer below:

$\frac{x^{4}1}{x^2}$

$2x\frac{2}{3}$

$\frac{1}{3x^3}(9x^{2}4x-3)$

$\frac{3x^{2}3}{x}$

$5$earch